Sort Python Dictionary by Values/Keys
A- create a dictionary- items_count = {' are': 1, 'hi': 2, 'me': 3, 'you': 5} B- Sort by values of dict - sorted_x = sorted(items_count.items(), key=lambda kv: kv[1], reverse= True) Sorted_x [('you', 5), ('me', 3), ('hi', 2), ('are', 1)] #op sorted() have a key parameter to specify a function to be called on each list element prior to making comparisons. by default ascending oreder, if reverse = True then reverse order. items_count.items()- dict_item data type that items_count as tuples. kv: kv[1] function that takes 2nd value from each tuple so that comparison happens for values not keys. kv:kv[0] would have sorted by keys of dictionary. C- convert list to dictionary again- import collections sorted_dict = collections.OrderedDict(sorted_x) OrderedDict([('you', 5), ('me', 3), ('hi', 2), ('are', 1)]) #op creates dictionary from list to have dictionary ...