Sort Python Dictionary by Values/Keys

A-  create a dictionary-

items_count= {'are': 1, 'hi': 2, 'me': 3, 'you': 5}

B- Sort by values of dict -

 sorted_x = sorted(items_count.items(), key=lambda kv: kv[1], reverse= True)

 Sorted_x

 
[('you', 5), ('me', 3), ('hi', 2), ('are', 1)]  #op
sorted() have a key parameter to specify a function to be called on each list element prior to making comparisons. by default ascending oreder, if reverse = True then reverse order.
items_count.items()- dict_item data type that items_count as tuples.
kv: kv[1] function that takes 2nd value from each tuple so that comparison happens for values not keys.

kv:kv[0] would have sorted by keys of dictionary.

C- convert list to dictionary again-

 import collections sorted_dict = collections.OrderedDict(sorted_x)

 
OrderedDict([('you', 5), ('me', 3), ('hi', 2), ('are', 1)]) #op

 creates dictionary from list to have dictionary as output data type


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